(4x^2+3x+5)-(4x^2-3x+5)=

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Solution for (4x^2+3x+5)-(4x^2-3x+5)= equation:


Simplifying
(4x2 + 3x + 5) + -1(4x2 + -3x + 5) = 0

Reorder the terms:
(5 + 3x + 4x2) + -1(4x2 + -3x + 5) = 0

Remove parenthesis around (5 + 3x + 4x2)
5 + 3x + 4x2 + -1(4x2 + -3x + 5) = 0

Reorder the terms:
5 + 3x + 4x2 + -1(5 + -3x + 4x2) = 0
5 + 3x + 4x2 + (5 * -1 + -3x * -1 + 4x2 * -1) = 0
5 + 3x + 4x2 + (-5 + 3x + -4x2) = 0

Reorder the terms:
5 + -5 + 3x + 3x + 4x2 + -4x2 = 0

Combine like terms: 5 + -5 = 0
0 + 3x + 3x + 4x2 + -4x2 = 0
3x + 3x + 4x2 + -4x2 = 0

Combine like terms: 3x + 3x = 6x
6x + 4x2 + -4x2 = 0

Combine like terms: 4x2 + -4x2 = 0
6x + 0 = 0
6x = 0

Solving
6x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '6'.
x = 0

Simplifying
x = 0

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